(3x-4)^2-(x-7)^2=8x(x-2)

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Solution for (3x-4)^2-(x-7)^2=8x(x-2) equation: 



(3x-4)^2-(x-7)^2=8x(x-2)

We move all terms to the left:

(3x-4)^2-(x-7)^2-(8x(x-2))=0



We calculate terms in parentheses: -(8x(x-2)), so:

8x(x-2)

We multiply parentheses

8x^2-16x

Back to the equation:

-(8x^2-16x)



We get rid of parentheses

-8x^2+(3x-4)^2-(x-7)^2+16x=0

We add all the numbers together, and all the variables

-8x^2+16x+(3x-4)^2-(x-7)^2=0

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